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/cvs/deliantra/server/common/object.C
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Comparing deliantra/server/common/object.C (file contents):
Revision 1.191 by root, Sun Sep 30 20:22:15 2007 UTC vs.
Revision 1.194 by root, Tue Oct 16 00:30:24 2007 UTC

254 /* This is really a spellbook check - really, we should 254 /* This is really a spellbook check - really, we should
255 * check all objects in the inventory. 255 * check all objects in the inventory.
256 */ 256 */
257 if (ob1->inv || ob2->inv) 257 if (ob1->inv || ob2->inv)
258 { 258 {
259 /* if one object has inventory but the other doesn't, not equiv */ 259 if (!(ob1->inv && ob2->inv))
260 if ((ob1->inv && !ob2->inv) || (ob2->inv && !ob1->inv)) 260 return 0; /* inventories differ in length */
261 return 0;
262 261
263 /* Now check to see if the two inventory objects could merge */ 262 if (ob1->inv->below || ob2->inv->below)
263 return 0; /* more than one object in inv */
264
264 if (!object::can_merge (ob1->inv, ob2->inv)) 265 if (!object::can_merge (ob1->inv, ob2->inv))
265 return 0; 266 return 0; /* inventory objexts differ */
266 267
267 /* inventory ok - still need to check rest of this object to see 268 /* inventory ok - still need to check rest of this object to see
268 * if it is valid. 269 * if it is valid.
269 */ 270 */
270 } 271 }
305 { 306 {
306 ob1->optimise (); 307 ob1->optimise ();
307 ob2->optimise (); 308 ob2->optimise ();
308 309
309 if (ob1->self || ob2->self) 310 if (ob1->self || ob2->self)
310 if (!cfperl_can_merge (ob1, ob2)) 311 {
312 int k1 = ob1->self ? HvTOTALKEYS (SvRV (ob1->self)) : 0;
313 int k2 = ob2->self ? HvTOTALKEYS (SvRV (ob2->self)) : 0;
314
315 if (k1 != k2)
311 return 0; 316 return 0;
317 else if (k1 == 0)
318 return 1;
319 else if (!cfperl_can_merge (ob1, ob2))
320 return 0;
321 }
312 } 322 }
313 323
314 /* Everything passes, must be OK. */ 324 /* Everything passes, must be OK. */
315 return 1; 325 return 1;
316} 326}
1140merge_ob (object *op, object *top) 1150merge_ob (object *op, object *top)
1141{ 1151{
1142 if (!op->nrof) 1152 if (!op->nrof)
1143 return 0; 1153 return 0;
1144 1154
1145 if (top) 1155 if (!top)
1146 for (top = op; top && top->above; top = top->above) 1156 for (top = op; top && top->above; top = top->above)
1147 ; 1157 ;
1148 1158
1149 for (; top; top = top->below) 1159 for (; top; top = top->below)
1150 { 1160 {

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